Question

In the fig. ∠ABC = ∠CDE = 90⁰
AB = CD, BC = ED,

show that ∠ACE = 90⁰​

Answer 1

Answer:

f(A,B,C,D)=f(A,B,C,D)=AB+AC+BCD=(AB) (AC) (BCD) =(A+B) (A+C) (B+C+D)