In the Fig., ABCD is a parallelogram in which: LDAB= 80° and LDBC=60°. Find LCDB and LADB.
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ADB=DBC(Alternate interior angles)
ADB=60°
In triangle BCD
AngleBCD=DAB (opposite angles of parallelogram are equal)
angleBCD=80°
angleCDB+BCD+DBC=180°(angle sum property of triangle
CDB+80°+60°=180°
CDB=180°-140°
CDB=40°
ADB=60°
In triangle BCD
AngleBCD=DAB (opposite angles of parallelogram are equal)
angleBCD=80°
angleCDB+BCD+DBC=180°(angle sum property of triangle
CDB+80°+60°=180°
CDB=180°-140°
CDB=40°
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