Question

in the fig. angle ABC=90°
a)find the angle CBD
b)find the supplement of angle ABD

Answer 1

(2X+5)+(X-5)=90
Or, 3X=90
Or,X=30
So, angle CBD=25
b)And angle ABD=
$2 \times 30 + 5 = 65$
Then supplement of angle ABD=180-65=115

Answer 2

here ABC=90°
ABD = 2X+5°
DBC = X-5°
ABC = ABX+XBC
90° = 2X+5 + X-5
90° = 3X
i.e X = 30
1)CBD = X-5
=30-5
=25
2)ABD = 2X+5
= 2×30 + 5
= 60+5
=65
Supplement of ABD is 180-65
i.e 115°