In the fig., AOBCA represents the quadrant of a circle of radius 3.5 cm. Calculate the area of shaded portion. (Take π = 22/7)
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Step-by-step explanation:
We are given that radius of the quadrant =3.5cm
∴ Area of the quadrant AOBCA
=41πr2
=41×722×(3.5)2
=9.625cm2
Area of the triangle AOD
=21×base×height
=21×OA×OD
=21×3.5×2cm2
=3.5cm2
Hence Area of the shaded region =Area of the quadrant-Area of the triangle AOD
=9.625−3.5
=6.125cm2
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