Question

In the fig(ATTACHED) D is any point on side BC of of triangle ABC. prove that AB+BC+AC>2 AD
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Answer 1

Step-by-step explanation:

we know that in any traingle,the sum of two sides is greater than the third side.

in triangle ABD, AB+BD>AD.............eq(1)

similarly in triangle ACD,

AC+CD>AD.......................................eq(2)

On adding both equations,we get

AB+BD+AC+CD>AD+AD

AB+(BD+CD)+AC>2AD

AB+BC+AC>2AD (as BD+CD=BC)

hence proved....