In the fig below, point O is the center of the circle. find the value of ∠ACP if ∠ POB = 90 degrees i
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Step-by-step explanation:
Given
∠PBA = 45˚
AOB is diameter of circle.
∴ ∠APB = 90˚ (Angle in semi circle)
So in △APB, ∠PAB = 180˚ – (90˚ + 45˚)
= 45˚
∠PAB = ∠PQB (Angle in same segment)
∴ ∠PQB = 45˚
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