Question

In the fig. Cd is the perpendicular bisector of the chord ab . If ab =2cm and cd =4cm , calculatethe radius of the circle.

Answer 1

hey mate here is your solution
first see the diagram
in∆ ACD

ad=1cm (since ad=db )
cd=4cm
ac=radius of circle
now by Pythagoras theoram
in ∆ACD

$ac {}^{2} = ad {}^{2} + cd {}^{2}$

$ac {}^{2} = 1 {}^{2} + 4 {}^{2} \\ ac {}^{2} = 1 + 16 \\ ac = \sqrt{17}$
radii =√17 cm
radii=4.123cm