Question

In the fig given above, BC is a diameter of circle .If AB=AC find each angle of Triangle ABC


Please tell whole solution in clear way​

Answer 1

Answer:

Angle A = 90° ( angle in semi circle)

Angle B = Angle B ( angles opposite to equal sides are equal)

In ∆ ABC

Angle A+B+C = 180° ( Angle sum property)

90° + x+x = 180°

90° +2x= 180

2x=90°

x= 45°

hence, Angle A = 90°

Angle B = 45°

Angle C = 45°

hope you understand! :)