In the fig given above, BC is a diameter of circle .If AB=AC find each angle of Triangle ABC
Please tell whole solution in clear way
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Answer:
Angle A = 90° ( angle in semi circle)
Angle B = Angle B ( angles opposite to equal sides are equal)
In ∆ ABC
Angle A+B+C = 180° ( Angle sum property)
90° + x+x = 180°
90° +2x= 180
2x=90°
x= 45°
hence, Angle A = 90°
Angle B = 45°
Angle C = 45°
hope you understand! :)
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