Question

In the fig given, BC is a diameter of the circle. If AB=AC, find each angle of∆ABC.​

Answer 1

Answer:

∠BAC = 90°

∠ABC = 45°

∠ACB = 45°

Step-by-step explanation:

∠BAC = 90° [Angles in a semi-circle are equal to 90° (BC is diameter)]

∠ABC = ∠ACB [Angles opposite to equal sides are equal]

∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property)

90° + ∠ABC + ∠ACB = 180

∠ABC + ∠ACB = 180 - 90

∠ABC + ∠ACB = 90

2∠ABC = 90

∠ABC = 90/2 = 45

∠ABC = 45 = ∠ACB

Therefore,

∠BAC = 90°

∠ABC = 45°

∠ACB = 45°