In the fig given below DE||BC find the value of x
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Answer:45°
Step-by-step explanation:
Given DE||BC
⇒∠C +∠E = 180°(Co-interior angles are supplementary)
⇒∠C + 95° =180°
⇒∠C = 180° - 95°= 85°
Now, In ΔABC,
∠A+ ∠B+ ∠C =180° (Angle Sum Property)
⇒ x + 50° + 85° = 180°
⇒ x + 135° = 180°
⇒ x = 180° - 135°= 45°
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