Question

In the fig given here, AB || DC || EF , AD || BC and ED || FA. Prove that area of parallelogram DEFH is equale to the area of parallelogram ABCD.

Answer 1

જશે ઝસજસ હસાજસ sbs sbs શબ્દ સસ્સ બિસ્ક

Answer 2

Answer: Proved.

Step-by-step explanation: Let us modify the given figure in the attached figure.

In the modified figure, we have the following

AB || DC and AD || BC, which gives that ABCD is a parallelogram. In the same manner, we can show that ADEG and DEFH are also parallelograms.

Now, we will use the following theorem

Two parallelograms standing on the same base and lying between the same pair of parallel lines have equal areas.

Since parallelograms ABCD and ADEG stand on the same base and lying between the same pair of parallel lines AD and BE. So, we have

Area of ABCD = Area of ADEG.

Again, since parallelograms ADEG and DEFH stand on the same base DE and lying between the same pair of parallel lines DE and AF.

Hence, we arrive at

Area of ADEG = Area of DEFH.

Hence proved.