In the fig. if O is the center of the circle,<AOB = 50° and <ACO=20°.Find the measure of <BOC.
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Given angle ABO = 50° And angle ACO = 20°
To find angle BOC
Now in triangle AOB
<ABO = <OAB = 50°.
( Angle opposite to equal sides ( radii) )
Now,
< AOB = 180° - 100° = 80°. ( By angle sum property)
Similarly in triangle AOC
< CAO = 20°
and <AOC = 180° - 40° = 140°
Since
<AOC + <AOB + <BOC = 360°
140° + 80° + < BOC = 360°
220° + <BOC = 360°
<BOC = 360° - 220° = 140°. Ans.....
Hope helped !!!
To find angle BOC
Now in triangle AOB
<ABO = <OAB = 50°.
( Angle opposite to equal sides ( radii) )
Now,
< AOB = 180° - 100° = 80°. ( By angle sum property)
Similarly in triangle AOC
< CAO = 20°
and <AOC = 180° - 40° = 140°
Since
<AOC + <AOB + <BOC = 360°
140° + 80° + < BOC = 360°
220° + <BOC = 360°
<BOC = 360° - 220° = 140°. Ans.....
Hope helped !!!
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