in the fig if triangle abc is and isosceles triangle with AC= BC finds the value of x
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Step-by-step explanation:
as AC=BC
<A=<B=70°
external angle of a triangle is equal to sum of opposite angles
<x =<A+<B
= 70+70=140
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Given : ∆ABC is an isosceles triangle with AC=BC
To Find : value of x
Solution:
AC = BC
Angles opposite to Equal sides are Equal
∠B= ∠A
=> ∠B = 70°
x = ∠A + ∠B ( Exterior angle = Sum of opposite interior angles)
=> x = 70° + 70°
=> x = 140°
value of x. = 140°
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