Question

in the fig , line AB and CD intersect at O angle BOC = 63 , find x,y,z​

Answer 1

Answer:

x=117°,y=63°,z=117°

Step-by-step explanation:

ΔBOC+ΔAOC=180°

63°+x=180°

x=180°-63°

x=117°

ΔBOC=ΔAOD(Vertically opposite angle)

63°=63°

ΔCOA=ΔBOD(vertically opposite angle)

117°=117°

That's solve

Answer 2

Question :

In the fig,line AB and CD intersects at O. ∠BOC = 63°,find x,y and z.

Given :

• ∠BOC = 63°

To find :

• Value of x,y and z

According to the question,

→ ∠BOC = 63°

→ ∠BOC = ∠AOD = 63°

Reason :- Vertically opposite angle

→ ∠BOC + ∠DOB = 180°

Reason :- Linear Pair

→ 63° + z = 180°

→ z = 180° - 63°

→ z = 117°

→ ∠DOB = ∠COA = 117°

→ z = x = 117°

Reason :- Vertically opposite angle

So,

• The value of x = 117°
• The value of z = 117°
• The value of y = 63°

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