In the fig., lines PQ and RS intersect each other at point 0. If ZPOR: ZROQ = 5:7,
find all the angles.
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2
Answer:
P,Q,R,S - 5:4 intersect each other points at 2
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12
Answer:
Since angle POR: angle ROQ=5:7
Let the ratio be 5x:7x
POR+ROQ=180 (Linear pair)
5x+7x=180
12x=180
x=15
Therefore angle POR=5x
=5×15
=75=angle POR
And angle ROQ=7x
=7×15
=105=angle ROQ
Angle POS = Angle ROW (Vertically opposite angle)
Angle POS= 105
ANGLE SOQ= ANGLE POR (V.O.A)
ANGLE SOQ = 75
I HOPE THIS HELPS YOU
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