In the fig. (not drawn to scale) a rocket is fired vertically upwards from its launching pad p. It Frist rises 20 km vertically up and then travels 80 km at 30° to the vertical. PA represents the Frist state of its journey and AB the second; C is the point 0 vertically below B on the same horizontal level as P. calculate:
i) The height of the rocket when it is at point B.
ii) The horizontal distance of point C From point P.
______________________________________
please do correctly !!
Answers
Answered by
132
Hey !
here's your answer ❗
________________________________________________________________________
BC =?
PC =?
PC = x = ?
BC = y + 20 = ?
In ∆ADB
sin 60° = y/80
√3/2 = y/80
80 = √3/2 = y
40√3 = y
(i) PC = x = 40km
BC = y + 20
= 40√3 + 20
(20 + 40√3) km
ii) Cos 60° = x/80
1/2 = 80
x = 80/2
x = 40 km
________________________________________________________________________
glad help you
it helps you
thank you ☺
@vaibhavhoax
here's your answer ❗
________________________________________________________________________
BC =?
PC =?
PC = x = ?
BC = y + 20 = ?
In ∆ADB
sin 60° = y/80
√3/2 = y/80
80 = √3/2 = y
40√3 = y
(i) PC = x = 40km
BC = y + 20
= 40√3 + 20
(20 + 40√3) km
ii) Cos 60° = x/80
1/2 = 80
x = 80/2
x = 40 km
________________________________________________________________________
glad help you
it helps you
thank you ☺
@vaibhavhoax
Attachments:
Steph0303:
:)
Great, mark it as brainliest
Answered by
39
Hey mate.....
here's ur answer.....
Hope it helps....
Be brainly...
here's ur answer.....
Hope it helps....
Be brainly...
Attachments:
Similar questions