In the fig., o is the center of the circle. If angle OUT is 90 degree, find angle ACB.
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since angle AOB=120°
angle ACB =60°
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Answer : 60°
Step-by-step explanation :
O is center that's why OA and OB will be radius.
So, OA = OB [ Radius are always same ]
∠OAB = ∠OBA
Here, ∠OAB = 30°
So, ∠OBA = 30°
Due to angle sum property
∠OAB + ∠OAB + ∠AOB = 180°
30° + 30° + ∠AOB = 180°
∠AOB = 180° - 60° = 120
Since angle subtended by an arc with center is twice the angle subtended by arc at rest if circle.
∠AOB = 2∠ACB
120° = 2∠ACB
60° = ∠ACB
Step-by-step explanation :
O is center that's why OA and OB will be radius.
So, OA = OB [ Radius are always same ]
∠OAB = ∠OBA
Here, ∠OAB = 30°
So, ∠OBA = 30°
Due to angle sum property
∠OAB + ∠OAB + ∠AOB = 180°
30° + 30° + ∠AOB = 180°
∠AOB = 180° - 60° = 120
Since angle subtended by an arc with center is twice the angle subtended by arc at rest if circle.
∠AOB = 2∠ACB
120° = 2∠ACB
60° = ∠ACB
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