In the fig. O is the centre of a circle , AB is a diameter, m (arc AXM ) = 60° then find
m ZBOM
B.
O
A
Y
X
M
Answers
Answered by
2
Step-by-step explanation:
In a circle angle subtended by any chord on opposite sides are supplementary.
So m(arcAPC)+m(arcABC)=180
o
So m(arcABC)=180
o
−60
o
=120
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