in the fig PQ=PR nd SP is parallel to QR.if angle SPQ =75 find angle QPR
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TheLostMonk:
QPR=30°
Answers
Answered by
2
Given that PQ = PR
angle SPQ =60°
"If any two lines of equal length intersects any two parallel lines, then the angle made with parallels by those two lines are equal, starts from a point on any of those two parallels"
which represents angle APR = angle SPQ
to get the angle at P 75°+angle P + 75° = 180( angle made by line is 180°
angle P = 30°
Any doubts comment ;)
angle SPQ =60°
"If any two lines of equal length intersects any two parallel lines, then the angle made with parallels by those two lines are equal, starts from a point on any of those two parallels"
which represents angle APR = angle SPQ
to get the angle at P 75°+angle P + 75° = 180( angle made by line is 180°
angle P = 30°
Any doubts comment ;)
Answered by
1
Given- PQ=PR
Angle SPQ=75°
TO FIND- angle QPR
angle PQR=75° (alternate angle)
angle PRQ = 75° (opposite angle of equal side is equal)
Angle QPR+ angle PQR+ angle PRQ=180°( angle sum property)
QPR + 75 + 75 = 180
QPR + 150 = 180
QPR = 180-150
QPR=30°
Therefore angle QPR = 30°
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