Question

In the fig. PQR is a right angled triangle and two angles are 45°-45° and the length of hypotenuse side is
6V3 cm, find the side PQ and side QR

Answer 1

Answer:

Given, PQ = 10 cm, PR = 24 cm and QR =?

By applying Pythagoras theorem in triangle PQR, we get (Hypotenuse)2 = (Perpendicular)2 + (Base)2

(QR)2 = (PQ)2 + (PR)2

(QR)2 = (10)2 + (24)2

(QR)2 = 100 + 576

(QR)2 = 676

QR = 26 cm

Thus, QR is equal to 26 cm.

Answer 2

Answer:

Given: PQ = 10cm, PR = 24cm.

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse) 2 = (Base) 2 (Perpendicular)2

[By Pythagoras theorem]

⇒(QR) 2 = (PQ) 2 + (PR) 2

⇒ x 2 = (10)

2 + (24) 2

⇒ x 2 = 100 + 576 = 676

⇒ x= 676 = 26cm

Thus, the length of QR is 26 cm.

$thank \: you$