Question

In the fig PS bisector of l and RQ bisector l find the measure of y

Answer 1

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Here is your answer ↓⬇


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▶
$\huge \bf \sf{It \: is \: given \: that:-)}$


↪➡
$\bf { PS \perp \: L.}$


↪➡
$\bf{RQ \perp \: L}$


↪➡
$\bf{ \angle \: PRQ = 55°. }$


↪➡
$\bf{ \angle \: SRT = 135°.}$


▶ Now, PT is a line.


$\boxed{ \angle SRT + \angle SRP = 180°........[ Linear \: pair ].}$

$\bf{=> 135° + \angle SRP = 180°.}$

$\bf{=> \angle SRP = 180° - 135°}.$


$\bf{=> \angle SRP = 45°.}$



▶Now,


$\bf{=> \angle SRQ = \angle SRP + \angle PRQ .}$


$\bf{=> \angle SRQ = 45° + 55°.}$



$\huge \bf{=> \angle SRQ = 100°.}$


▶Now, PQRS is quadrilateral.

▶ Then .


$\boxed{ \angle QPS + \angle PSR + \angle \: SRQ + \angle RQP = 360°.}$

$\bf{=> 90° + \angle \: y + 100° + 90° = 360°.}$


$\bf{=> \angle \: y + 280° = 360°.}$


$\bf{=> \angle y = 360° - 280°.}$


$\huge \boxed{=> \angle y = 80°.}$


✅✅ Hence, the value of ‘y’ is founded ✔✔.



$\huge \boxed{THANKS}$



$\huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}$

Answer 2

Answer:

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