Question

In the fig. seg AB || seg CD || seg EF AC = 15, BD = 10, DF = 6 then AE =?​

Answer 1

Answer:

AC/CE=BD/DF

Step-by-step explanation:

15/CE=10/6

CE=15×6/10

CE=3×6

CE=18

AE=AC+CE

AE=15+18

AE=33

Answer 2

Answer:

In figure

seg AB ll seg CD ll seg EF

By three lines parallel and it transversal

AC/ CE = BD/ DF

15/ CE=10/6

CE=15×6/10

CE=9

=AC+ CE= 15+9= 24