in the fig. show that AB is parallel to EF
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53
Angle BCE+ Angle ECD= Angle BCD
36°+30°= 66°
Angle ABC= Angle BCD
[Reason: Interior Alternate Angles are equal]
Therefore AB || CD
Given: EF is || to CD
Therefore EF || AB
Hence Proved!
HOPE IT HELPS! ^_^
36°+30°= 66°
Angle ABC= Angle BCD
[Reason: Interior Alternate Angles are equal]
Therefore AB || CD
Given: EF is || to CD
Therefore EF || AB
Hence Proved!
HOPE IT HELPS! ^_^
Answered by
16
Extend CE then then,
EF || CD (corresponding angle)
AB||CD (alt. int. angle)
Thus, AB || EF (PROVED)
EF || CD (corresponding angle)
AB||CD (alt. int. angle)
Thus, AB || EF (PROVED)
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