In the Fig. show that ABCD is a parallelogram
DC=5cm,DB=7cm,AB=5cm.
Calculate the area of Ilgm ABCD.
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that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that DE∣∣AB,AD=7 cm, CD=5 cm and BC=18 cm.
Using the basic proportionality theorem, we have
CA
CD
=
AB
DE
=
CB
CE
⇒
CA
CD
=
CB
CE
⇒
12
5
=
18
CE
⇒18×5=12CE
⇒12CE=90
⇒CE=
12
90
=7.5
Since CE=7.5 cm, therefore,
CB=CE+EB
⇒18=7.5+EB
⇒EB=18−7.5=10.5
Hence, BE=10.5 cm and CE=7.5 cm.
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