Question

in the fig ,the total height is 20.5cm.the height of the cone which is one end is 3.5cm and heightbof cylindrical part is 10cm ,find the volume of thr toy​

Answer 1

CORRECT QUESTION :

In the fig ,the total height is 20.5 cm. the height of the cone which is one end is 3.5cm in radius and height of cylindrical part is 10cm ,find the volume of the toy.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Volume\:of\:toy=539\:cm^{3}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{given : }} \\ \tt{: \implies Total \: height = 20.5 \: cm} \\ \\ \tt{: \implies Height \: of \: cylindrical \: part = 10 \: cm} \\ \\ \tt{: \implies Radius \: of \: cone = Radius \: of \: cylinder = 3.5 \: cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ \tt{: \implies Volume \: of \: toy =?}$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt{: \implies Volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h }\\ \\ \tt{: \implies Volume \: of \: cone = \frac{1}{3} \times \frac{22}{7} \times {(3.5)}^{2} \times 10.5} \\ \\ \tt{: \implies Volume \: of \: cone =22 \times 6.125} \\ \\ \green{\tt{: \implies Volume \: of \: cone =134.75 { cm}^{3}}} \\ \\ \bold{As \: we \: know \: that} \\ \tt{: \implies Volume \: of \: cylinder = \pi {r}^{2} h }\\ \\ \tt{: \implies Volume \: of \: cylinder= \frac{22}{7} \times {(3.5)}^{2} \times 10.5} \\ \\ \tt{: \implies Volume \: of \: cylinder =22 \times 18.375} \\ \\ \green{\tt{: \implies Volume \: of \: cylinder = 404.25 { cm}^{3}}} \\ \\ \bold{for \: Total \: volume} \\ \tt{: \implies Volume \: of \: toy = Volume \: of \: (cone + cylinder)} \\ \\ \tt{: \implies Volume \: of \: toy =134.75 + 404.25} \\ \\ \green{\tt{: \implies Volume \: of \: toy =539 {cm}^{3}}}$