in the figue ABCD is a square and EF parallel BD . PROVE BE = DF
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Saadhana:
Is DB angular bisector ??
Your question is wrong give proper details
it is right
no this answer is complete guyz
miss sadhna it is not given that DB is angular bisector but it is because DC = BC ( side of square ) .
thrfr angle CDB = angle CBD . and this question is class for 9th and this question is came in my SA2 exams .
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ABCD is a square ,
=> AB=BC=CD=DA,
=> BC=DC,
also, DB || EF, (given)
=> Distance between lines DB and EF is equal at every point.
Thus, DF=BE,
Hence Proved...
Hope it helps
=> AB=BC=CD=DA,
=> BC=DC,
also, DB || EF, (given)
=> Distance between lines DB and EF is equal at every point.
Thus, DF=BE,
Hence Proved...
Hope it helps
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