in the figuer, the area of a parallelogram ABCD , the area of triangelADE is 24cmsquare is
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hii MATE
what we have to do in this question??
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jai mahakal
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traingle ADE and parallelogram ABCD lie on same base AD and between same parallels AD AND BC.
BY THEROEM
We get that
ar(ADE) = 1/2ar(ABCD)
24 = 1/2 ar(ABCD)
24*2 = ar(ABCD)
48 = ar(ABCD)
THEREFORE AREA OF PARALLELOGRAM ABCD IS 48cm.
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