In the figure (1) given below, PQ = 24 cm, QR = 7 cm and PQR = 90°. Find the
radius of the inscribed circle of APQR.
(2012)
(b) In the figure (ii) given below, two concentric circles with centre o are
5 cm and 3 cm. From an external point P, tangents PA and PB are drawn to the
circles. If AP = 12 cm, find BP.
cm
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radius of the inscribed circle of ΔPQR = 3 cm
Step-by-step explanation:
PQ = 24 cm, QR = 7 cm and ∠PQR = 90°
=> area of triangle = (1/2) 7 * 24 = 84 cm²
hypotenuse = √24² + 7²
=> hypotenuse = √476 + 49
=> hypotenuse = √525
=> hypotenuse = 25 cm
Area of Triangle = (1/2) (7 + 24 + 25) * r
r = Radius of inscribed circle
=> 84 = (1/2) (56 ) r
=> r = 3
radius of the inscribed circle of ΔPQR = 3 cm
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Where is the figure???
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