In the figure 10.12, if ZBAO = ZDCO and OC = OD, show that AB || CO.
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Step-by-step explanation:
- in triangle bao and dco
- => angle BOA =angle DOC (V.O.A)
- => AO=OC (side opp. to eq. angles are equal)
- => OD=BO (side opp. to eq. angles are equal)
- hence triangle bao and dco are congruent triangle (by SAS criteria)
- AngleABO=AngleOCD (BY C.P.CT)-----(1)
- From (1) we get.
- ABIICD (AngleABO=OCD are alt. int angles)
- H.P
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