in the figure 10.13 angle A is equals to 75 degree and c e parallel to a b if angle ACD equals to 40 degree find the other two angles of the triangle ABC
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Answer:
B= 40°, C = 65°
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angel ACE = angel BAD= 75 bcoz of interior alternate angel
now angel ACB equal to... 180-(75+40 )= 65 due to linear pair...
now sum of all angel of triangel is 180...so angel ABD will be... 180-(65+75) = 40
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