In the figure 10.15, show that:
A
9.
B
40
(i) AB|| CD
E
F
(ii) CD || EF
160°
20
20°
(iii) AB ||EF
D
Fig. 10.15
Justify your answer.
please guys it's urgent please help me
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Answer:
Step-by-step explanation:
since
angle ABC = 40 = Angle ( BCE+ECD) , so these makes alternate interior angle..
so AB || CD
now angle ECD + angle CEF = 20°+ 160° = 180° (adjacent angles) so EF||CD
and because CD is parallel to both AB and EF
SO, AB||EF
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