Question

In the figure 11.23 solve the question

Answer 1

Hi frnd ! It's easy just break your figure into 2 figures i.e rectangle and triangle .
Construct a line parallel to SP from R on PQ . Let's call it z

So PZ + ZQ = PQ = 60 cm.......1
PZ will be equal to SR
So PZ = SR = 36 cm........2

Substitute 2 in 1
So 36 + ZQ = 60 cm
ZQ = 60 - 36
ZQ = 24 cm
Now
apply Pythagoras theorem in triangle RZQ
By this u will get RZ and then you can find the area of triangle

RZ will be equal to SP , so from that you can find the area of rectangle.

Now add the area of triangle to the area of rectangle. Then you will get the area of figure.
I hope this helps!!!!