) In the figure (2) given below, AABC is right-angled at B. If AB = y units,
BC = 3 units and CA = 5 units, find
sin x°
y
Answers
Given :-
:-AC= hypotenuse side = 5 units
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 units
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4 AB= 4 units
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4 AB= 4 unitssin x° = opposite side/ hypotenuse side
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4 AB= 4 unitssin x° = opposite side/ hypotenuse side = AB/AC
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4 AB= 4 unitssin x° = opposite side/ hypotenuse side = AB/AC = 4/5
:-AC= hypotenuse side = 5 unitsBC= adjacent side = 3 unitsBy using pythagoras therom(AB)^2 = (AC)^2 -(BC)^2 = 5^2-3^2 = 25-9(AB)^2 = 16 AB =√16 =4 AB= 4 unitssin x° = opposite side/ hypotenuse side = AB/AC = 4/5 sin x° = 0.8
sin x° = 0.8 I believe this anwer will be useful for you!
for clear reference verify the above photos.