Question

In the figure (2), l║m and a line t intersects these lines at P and Q
respectively. Find 2a + b, c and d

Answer 1

From the above figure, we can say that

∠AQB = ∠FQP [vertically opposite angles]

b = 132°

Since, l, m are parallel lines and t is transversal.

$\sf \therefore, ∠EPD = ∠PQF \: \: \: \: \: \: \: [corresponding \: angles]$

A = 132°

Now,

2a + b = 2 x 132° + 132°

= 264° + 132°

= 396°

Answer 2

Answer:

If l parallel to m and t is a transversal intersecting them,then

angle a=132°(corresponding angles are equal)

angle b=132°(vertically opposite angles are equal)

angle c+132=180°(co interior angles are supplementary)

angle c=180-132

angle c=48°

angle d=angle c(vertically opposite angles are equal)

angle d=48°

therefore

2a+b=2×132+132

264+132=396

angle c=48°

angle d=48°