In the figure 3,AB||CD,find the value of x
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180°=130° + y°
y° = 50°
180° = 20° + x° + 50°
x° = 110°
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Given that AB parallel to DC
Construction - Line AQ passing through C (As shown in the figure)
Now,
In Triangle CQE :-
From Exterior angle property of the triangle we can say that :-
Angle 1 + Angle E = 130
Angle 1 = 130 - 20 =110
(since, Angle E =20 given)
Now,
Since,
AB parallel to DC we have :-
Angle x = Angle 1
(They are corresponding angles)
Hence,
Angle x = 110 degrees.
Thus,
Value of x is 110 degrees.
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