in the figure(3) given below,AC=CD.prove that BC<CD
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Answer:
where's the figure???
Step-by-step explanation:
ANSWER
∠ABC+73+74=180
∠ABC=180−147
∠ABC=33
o
∠ACD=180−74=106
2x+106=180
2x=180−106=74
x=37
∠CAB=110−37=73
o
According to their angle we can prove BC>CD.
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