In the figure, 4 quadrants, each of radius 2 m, are removed from a rectangle. Find the perimeter, the area of the figure.
Answers
Answer:
3.5 M^2
Step-by-step explanation:
4 Quadrants are equal to 1 circle.
Ar circle= 22/7 *2 *2
=88/7 m^2
Ar rectangle= 4*4= 16m^2
REMAINING AREA = 3.5 M^2
In the figure, 4 quadrants, each of radius 2 m, are removed from a rectangle.
I have attached the required figure, assuming the sides of a rectangle based on given measurement of quadrants.
Let the sides of a rectangle be 2 m × 4 m.
The radius of quadrant is 2 m ( given )
From given, we have,
Area of figure = Area of 4 quadrants - Area of rectangle .
= 4 × π/4 × r² - l × w
= 4 × π/4 × 2² - 2 × 4
= 3.14 × 4 - 8
= 12.4 - 8
= 4.4 m²
Therefore, the area of the figure is 4.4 m²
Perimeter of figure = Perimeter of 4 quadrants - Perimeter of rectangle
= 4 × [ 0.5πr + 2r ] - 2 ( l + w )
= 4 × [ 0.5 × 3.14 × 2 + 2 × 2 ] - 2 ( 4 + 2 )
= 4 × [ 3.14 + 4 ] - 2 (6)
= 28.56 - 12
= 16.56 m
Therefore, the perimeter of the figure is 16.56 m
