Question

In the figure 6.21, CD is a diameter
of the circle with centre 0. Diameter
CD is perpendicular to chord AB at
point E. Show that A ABC is an
isosceles triangle.​

Answer 1

Answer:

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Answer 2

Answer:

Given : CD is the diameter with centre O , CD perpendicular to chord AB at point E

To prove : triangle ABC IS isocelous triangle

Solution : IN triangle ABC ,

OE is perpendicular to AB so

AE = EB.....(1).....perpendicular drawn from the centre of the circle to a chord bisects the chord

Angle CEA = CEB..... (2)....CE IS PERPENDICULAR

SIDE CE=CE. ....(3)....SAME SIDE

THEREFORE , FROM 1 , 2 AND 3

CAE = CBE ....BY SAS TEST

THEREFORE CA=CB....(4)...C.S.C.T.

From (4)...TRIANGLE ABC IS ISOCELOUS TRIANGLE , HENCE PROVED

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Step-by-step explanation: