Question

In the figure A and B are points on a circle with center O . If A ( 1,3) and B (-2,b) then b is pls explain and Answer this question ? 10th CBSE .​

Answer 1

Answer:

Given, x=80

o

.

In given circle , O is center and points A and B lies on circle.

So, AO and BO are equal as they are the radius.

Since AO and BO are equal, the angles opposite to that sides are equal.

Therefore z=x=80.

Therefore the correct option is A.

Answer 2

Answer:

The value of b is $\sqrt{6}$

Step-by-step explanation:

Given:

$A(1,3)\\\\B(-2,b)$

If the center is at the origin $O(0,0)$

The distance between the points is the same from the center of the circle

The distance formula for points $(x_1,y_1)$ and $(x_2,y_2)$ is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So we get as:

$\sqrt{(1)^2+(3)^2}=\sqrt{(-2)^2+(b)^2}\\\\\sqrt{10} =\sqrt{b^2+4}$

$b^2+4=10\\\\b^2=6\\\\b=\sqrt{6}$