Question

In the figure a and b are the midpoints of equal to chords PQ and RS respectively of circle centre O prove that ∆OAQ ≈ ∆OBS

HELP ME!!!!!!!!

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Answer 1

Step-by-step explanation:

in triangle OAQ & OBS,

• AQ=BS ... ( since PQ=RS, and A & B are the respective mid points)
• angle OAQ =angle OBS ... (90' each)
• OQ = OS ... (radius of the same circle)

therefore, by RHS criteria, both the triangles will be congruent. Also, we know that two congurent figures must be similar to.

thus, OAQ similar to OBS