Question

in the figure A,B,C are points on a circle with centre 'o' find the angles of the triangle ABC​

Answer 1

Answer:

the question is written in a vague manner ...resend it properly

Answer 2

Answer:

here's your answer mate

Step-by-step explanation:

center = O

and angle OBC = 10

angle OCB = 20

In ∆OBC

∆ property

angle OBC + angle OCB + angle BOC = 180

10 +20 + angle BOC = 180

angle BOC = 150

by theorem 10.8 of class 9

angle BOC = 2 × angle BAC

150 /2 = angle BAC

angle BAC = 75

hope it helps you

plzzzzzzzzz markk meee assss brainliestttttt