In the figure, ∆A’B’C’ is an enlargement of ∆ABC with a scale factor of 2.5. Given that AB = 4cm
and AC = 5cm, find the length of A’B’ and of A’C’.
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△ABC is enlarged to △A′B′C′,
Thus, CAC′A′=2.5
Therefore, 4C′A′=2.5
⇒C′A′=4×2.5
⇒C′A′=10 cm
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