Question

in the figure a circle touches all the four sides of a quadrilateral ABCD whose sides are AB is equals to 8 cm BC is equals to 7 cm and CD is equals to 5 cm find AD .​

Answer 1

6 CM

Step-by-step explanation:

AP=AS....(1)

BP=BQ....(2)

CR=CQ....(3)

DR=DS....(4)

SINCE TANGENTS DRAWN FROM AN EXTERNAL POINT TO A CIRCLE ARE EQUAL.

BY ADDING (1),(2),(3)&(4)

WE GET,

AP+BP+CR+DR=AS+BQ+CQ+DS

->(AP+BP)+(CR+DR)=(AS+DS)+(BQ+CQ)

->(8)+(5)=(AD)+(7)

->13=AD+7

->AD=13-7

->AD=6CM

Answer 2

Answer:

Step-by-step explanation: