in the figure a cyclist moves from A to B and then to c. he could go through the shortest path AC. despending on this fact if he takes 2 seconds to move from A to B and 1 seconds from B to C find his average speed
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Answer:
0.0023 m/s²
Explanation:
Average speed = Total distance travelled / Total time taken
= 4 + 3 Km / 2 + 1 s
= 7 Km / 3 s
We need to convert Km to m, so 7 Km = 7/1000 m = 0.007 m
Average speed = Total distance travelled / Total time taken
= 0.007 m / 3 s
= 0.0023 m/s².
Hope this is the correct answer and it helps.
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