in the figure a is the bisector of angle C A D and AE||BC. prove that triangle ABC is an isosceles triangle
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Step-by-step explanation:
SINCE
AB||BC
AD is transversal
therefore,
angle2=angleB.-------------------1
NOW In triangle ABC
by ext. angle property
angle B + angle C=ANGLE CAD
ANGLE 2+ ANGLE C=ANGLE 1+ ANGLE 2
=>angleC=angle1-------------------------2
now,/_1=/_2
therefore
angleB= angleC
AC=AB(sides opp. to equal angles)
therefore
triangle ABC is an isosceles triangle
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