Question

in the figure A is the centre of the circle BD and CD are the tangents drawn if angle BDC =70 then angle BAC =​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest

pls refer the reference fig uploaded above

Step-by-step explanation:

now as bd and cd are tangents radii ab and radii ac would be perpendicular to given tangents

so this by tangent theorem

we get

angle abd=90 degrees and angle acd=90 degrees

so thus then considering quadrilateral abcd

use angle sum property for it

you get angle abd+angle bdc+angle dca+angle cab=360

ie angle cab+90+90+70=360

=360-250

thus angle cab=110 degrees