In the figure, a man of true mass M is standing on
a weighing machine placed in a cabin. The
cabin is joined by a string with a body of mass
m. Assuming no friction, and negligible mass of
cabin and weighing machine, the measured mass
of man is (normal force between the man and the
machine is proportional to the mass)
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Explanation:
The cabin is joined by a string a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass) The acceleration of man is mg(M+m). The acceleration of man is Mg(M+m).
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Answered by
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The cabin is joined by a string a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass) The acceleration of man is mg(M+m). The acceleration of man is Mg(M+m)
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