Question

in the figure a rectangle pqrs is inscribed in a circle with center T to prove arc PQ=arc SR= arc QR and arc SPQ= arcPQR​

Answer 1

Answer:

Given rectangle PQRS iscribed in aquadrant of a circle , with P at the centre and R on the circumference .And PS=12 cm and QP=5 cm.

In rightangle ΔPQR

(PR)

2

=(QP)

2

+(QR)

2

=(12)

2

+(5)

2

=144+25=169

⇒PR=13cm

The PR is the redius of circle

Then diameter =2×12=26cm

solution