Question

In the figure, A0Q and POB are straight
<A = 35º,< B = 40°,<P 38° and <Q = x. Find the value of x.​

Answer 1

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In △OAQ and △OBP, we have

        ∠A=∠B                   [Each equal to 90∘]

       ∠AOQ=∠BOP

So, by AA-criterion of similarity, we have

      △AOQ∼△BOP

⇒  Area(BOP)Area(△AOQ)=OP2OQ2

⇒ 150Area(△AOQ)=5272

⇒ Area(△AOQ)=2549×150cm2=294cm2

Answer 2

please mark as brainlist answer