In the figure AB==12cm ,AD=4cm
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2
Answer:
AB
2
=AD
2
+BD
2
AB
2
=25
⇒AB=5
AC
2
=AB
2
+CB
2
AC
2
=5
2
+12
2
AC
2
=169
⇒AC=13
cotθ=
AB
CB
=
5
12
.
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